Saturday, 7 February 2009

Math Challenge 15

This is an interesting one.

Given a special four-digit number, 1978,
we can get the centre two digit (97) by adding
the left-most 2 digits (19) and the right-most 2 digits (78).

Another of this special number is 1538.

Can you get 2 more of this special numbers?

Brain-raking isn't it?

To be frank, it is not that difficult.
Hint: Algebra can solve this maths thinker.

:-)
at

2 comments:

  1. Suresh S Murthy8 October 2009 at 3:35 am

    Hi,

    These are the numbers that match the requirement:
    [1208]
    [1318]
    [1428]
    [1538]
    [1648]
    [1758]
    [1868]
    [1978]
    [2307]
    [2417]
    [2527]
    [2637]
    [2747]
    [2857]
    [2967]
    [3406]
    [3516]
    [3626]
    [3736]
    [3846]
    [3956]
    [4505]
    [4615]
    [4725]
    [4835]
    [4945]
    [5604]
    [5714]
    [5824]
    [5934]
    [6703]
    [6813]
    [6923]
    [7802]
    [7912]
    [8901]

    I love your questions...

    ReplyDelete
  2. EeHai8 October 2009 at 10:39 pm

    Hi Suresh,
    I did not expect such a long list of numbers.
    However, I amazed at your answers. Well done! Yes, the answers are definitely correct. And as mentioned I do not think it is difficult.
    What I appreciate is the effort in trying. Maths is a wonderful subject for anyone wishing to put in effort.
    Cheers!

    ReplyDelete