Saturday, 7 February 2009

Math Challenge 15

This is an interesting one.

Given a special four-digit number, 1978,
we can get the centre two digit (97) by adding
the left-most 2 digits (19) and the right-most 2 digits (78).

Another of this special number is 1538.

Can you get 2 more of this special numbers?

Brain-raking isn't it?

To be frank, it is not that difficult.
Hint: Algebra can solve this maths thinker.

:-)

2 comments:

Suresh S. a.ka. Suri said...

Hi,

These are the numbers that match the requirement:
[1208]
[1318]
[1428]
[1538]
[1648]
[1758]
[1868]
[1978]
[2307]
[2417]
[2527]
[2637]
[2747]
[2857]
[2967]
[3406]
[3516]
[3626]
[3736]
[3846]
[3956]
[4505]
[4615]
[4725]
[4835]
[4945]
[5604]
[5714]
[5824]
[5934]
[6703]
[6813]
[6923]
[7802]
[7912]
[8901]

I love your questions...

EeHai said...

Hi Suresh,
I did not expect such a long list of numbers.
However, I amazed at your answers. Well done! Yes, the answers are definitely correct. And as mentioned I do not think it is difficult.
What I appreciate is the effort in trying. Maths is a wonderful subject for anyone wishing to put in effort.
Cheers!