Let's see an example of its application.

Solve 2

^{X}= 8. The solution is simple 2

^{X }= 2

^{3 }===> X = 3 (answer).

How about solving 2

^{X}= 5 ?

In this case, 5 cannot be expressed as a base of 2. So how?

Step 1: Perform

**logarithm**operation on BOTH sides.

**log**2

^{X}=

**log**5

Step 2: Using Power Law of Logarithm, it becomes x log 2 = log 5

Step 3: x = log 5 / log 2 = 0.699 / 0.301 = 2.322 (answer).

Is it simple?

This is one simple application of logarithm to solve a problem.

There are more, but with understanding of the above concept, it is easy to continue with its application. Cheers!

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