## Tuesday, 19 August 2008

### Log X Is Just A Number

I happened to come across an interesting mistake made by a maths student.

The mistake inter-mixed the principles of algebra with logarithm.

The maths question is to solve the value of x given the expression:

2+ log (5x - 1) = log 3x

The expression, after transferring the "log (5x -1)" to the right side of the "=", became

2 = log 3x - log (-5x + 1) !

Spotted the mistake done ?

Why was the "log (-5x + 1)" in that form?

The correct expression should be 2 = log 3x - log (5x - 1).

What actually went inside the student's mind was confusion between algebra and logarithm. He did not understand the concept of "logging" the (5x -1).

Log X is always a number!

Similarly log (5x - 1) is also a number.

Therefore log (5x - 1) moves as a number, same as in moving algebraic term.

If we have 2 + (x-a) = y, re-arranging the expression, gives us 2 = y - ( x-a).

The term "x-a" is taken as a whole, with change in the sign of (x -a) and not including that of the individual internal "a" and "x". This is basic algebra.

Moving log (5x - 1) is the same. Being a number, it operates equivalent to the algebraic manipulation.

The log (5x -1) is thus taken as a whole and sign change affects only the term as a whole. It does not affect the individual internal "5x" and "-1"!

Part of learning maths is following rules and principles.

The mistake made by the student was a reflection of correct algebraic change, but in the wrong sense. "Log" had converted the term into a number, and that was the mistake not captured.

Being careful with every steps taken in solving maths questions is a discipline one can treasure. This is one of the interesting part of doing maths!

<*_*>
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